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3x^2-4.6x-0.3=0
a = 3; b = -4.6; c = -0.3;
Δ = b2-4ac
Δ = -4.62-4·3·(-0.3)
Δ = 24.76
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4.6)-\sqrt{24.76}}{2*3}=\frac{4.6-\sqrt{24.76}}{6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4.6)+\sqrt{24.76}}{2*3}=\frac{4.6+\sqrt{24.76}}{6} $
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